4z+32=z+50

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Solution for 4z+32=z+50 equation: 



4z+32=z+50

We move all terms to the left:

4z+32-(z+50)=0

We get rid of parentheses

4z-z-50+32=0

We add all the numbers together, and all the variables

3z-18=0

We move all terms containing z to the left, all other terms to the right

3z=18

z=18/3

z=6

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