4z+3(6-z)=(z-1)+13

Solution for 4z+3(6-z)=(z-1)+13 equation:

4z+3(6-z)=(z-1)+13

We move all terms to the left:

4z+3(6-z)-((z-1)+13)=0

We add all the numbers together, and all the variables

4z+3(-1z+6)-((z-1)+13)=0

We multiply parentheses

4z-3z-((z-1)+13)+18=0


We calculate terms in parentheses: -((z-1)+13), so:

(z-1)+13

We get rid of parentheses

z-1+13

We add all the numbers together, and all the variables

z+12

Back to the equation:

-(z+12)


We add all the numbers together, and all the variables

z-(z+12)+18=0

We get rid of parentheses

z-z-12+18=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation