4z+27=3z+34

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Solution for 4z+27=3z+34 equation: 



4z+27=3z+34

We move all terms to the left:

4z+27-(3z+34)=0

We get rid of parentheses

4z-3z-34+27=0

We add all the numbers together, and all the variables

z-7=0

We move all terms containing z to the left, all other terms to the right

z=7

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