4z+1=bz+c

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Solution for 4z+1=bz+c equation:


Simplifying
4z + 1 = bz + c

Reorder the terms:
1 + 4z = bz + c

Solving
1 + 4z = bz + c

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-1bz' to each side of the equation.
1 + -1bz + 4z = bz + -1bz + c

Combine like terms: bz + -1bz = 0
1 + -1bz + 4z = 0 + c
1 + -1bz + 4z = c

Add '-1' to each side of the equation.
1 + -1bz + -1 + 4z = -1 + c

Reorder the terms:
1 + -1 + -1bz + 4z = -1 + c

Combine like terms: 1 + -1 = 0
0 + -1bz + 4z = -1 + c
-1bz + 4z = -1 + c

Reorder the terms:
1 + -1bz + -1c + 4z = -1 + c + 1 + -1c

Reorder the terms:
1 + -1bz + -1c + 4z = -1 + 1 + c + -1c

Combine like terms: -1 + 1 = 0
1 + -1bz + -1c + 4z = 0 + c + -1c
1 + -1bz + -1c + 4z = c + -1c

Combine like terms: c + -1c = 0
1 + -1bz + -1c + 4z = 0

The solution to this equation could not be determined.

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