4z+1-z=1+z=

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Solution for 4z+1-z=1+z= equation: 



4z+1-z=1+z=

We move all terms to the left:

4z+1-z-(1+z)=0

We add all the numbers together, and all the variables

4z-z-(z+1)+1=0

We add all the numbers together, and all the variables

3z-(z+1)+1=0

We get rid of parentheses

3z-z-1+1=0

We add all the numbers together, and all the variables

2z=0

z=0/2

z=0

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