4y=3(y-2)=2(y+4)-(2y-7)

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Solution for 4y=3(y-2)=2(y+4)-(2y-7) equation: 



4y=3(y-2)=2(y+4)-(2y-7)

We move all terms to the left:

4y-(3(y-2))=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

4y-3y+6=0

We add all the numbers together, and all the variables

y+6=0

We move all terms containing y to the left, all other terms to the right

y=-6

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