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4y=2/3(6y)
We move all terms to the left:
4y-(2/3(6y))=0
Domain of the equation: 36y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
4y-(+2/36y)=0
We get rid of parentheses
4y-2/36y=0
We multiply all the terms by the denominator
4y*36y-2=0
Wy multiply elements
144y^2-2=0
a = 144; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·144·(-2)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{2}}{2*144}=\frac{0-24\sqrt{2}}{288} =-\frac{24\sqrt{2}}{288} =-\frac{\sqrt{2}}{12} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{2}}{2*144}=\frac{0+24\sqrt{2}}{288} =\frac{24\sqrt{2}}{288} =\frac{\sqrt{2}}{12} $
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