4y=1/y

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Solution for 4y=1/y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

4*y = 1/y // - 1/y

4*y-(1/y) = 0

4*y-y^-1 = 0

4*y^1-1*y^-1 = 0

(4*y^2-1*y^0)/(y^1) = 0 // * y^2

y^1*(4*y^2-1*y^0) = 0

y^1

4*y^2-1 = 0

4*y^2-1 = 0

DELTA = 0^2-(-1*4*4)

DELTA = 16

DELTA > 0

y = (16^(1/2)+0)/(2*4) or y = (0-16^(1/2))/(2*4)

y = 1/2 or y = -1/2

y in { -1/2, 1/2} 

y in { -1/2, 1/2 }

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