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4y^2-81y=0
a = 4; b = -81; c = 0;
Δ = b2-4ac
Δ = -812-4·4·0
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6561}=81$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-81)-81}{2*4}=\frac{0}{8} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-81)+81}{2*4}=\frac{162}{8} =20+1/4 $
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