4y2+8y+4=0

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Solution for 4y2+8y+4=0 equation:



4y^2+8y+4=0
a = 4; b = 8; c = +4;
Δ = b2-4ac
Δ = 82-4·4·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-8}{8}=-1$

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