4y-7+2y=-3(y+1)-1

Solution for 4y-7+2y=-3(y+1)-1 equation:

4y-7+2y=-3(y+1)-1

We move all terms to the left:

4y-7+2y-(-3(y+1)-1)=0

We add all the numbers together, and all the variables

6y-(-3(y+1)-1)-7=0


We calculate terms in parentheses: -(-3(y+1)-1), so:

-3(y+1)-1

We multiply parentheses

-3y-3-1

We add all the numbers together, and all the variables

-3y-4

Back to the equation:

-(-3y-4)


We get rid of parentheses

6y+3y+4-7=0

We add all the numbers together, and all the variables

9y-3=0

We move all terms containing y to the left, all other terms to the right

9y=3

y=3/9

y=1/3