4y-7+2y=(y-1)-1

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Solution for 4y-7+2y=(y-1)-1 equation: 



4y-7+2y=(y-1)-1

We move all terms to the left:

4y-7+2y-((y-1)-1)=0

We add all the numbers together, and all the variables

6y-((y-1)-1)-7=0



We calculate terms in parentheses: -((y-1)-1), so:

(y-1)-1

We get rid of parentheses

y-1-1

We add all the numbers together, and all the variables

y-2

Back to the equation:

-(y-2)



We get rid of parentheses

6y-y+2-7=0

We add all the numbers together, and all the variables

5y-5=0

We move all terms containing y to the left, all other terms to the right

5y=5

y=5/5

y=1

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