4y-6+2y=8(y-2)

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Solution for 4y-6+2y=8(y-2) equation: 



4y-6+2y=8(y-2)

We move all terms to the left:

4y-6+2y-(8(y-2))=0

We add all the numbers together, and all the variables

6y-(8(y-2))-6=0



We calculate terms in parentheses: -(8(y-2)), so:

8(y-2)

We multiply parentheses

8y-16

Back to the equation:

-(8y-16)



We get rid of parentheses

6y-8y+16-6=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5

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