4y-6+2(4y+3)=-2(y+5)

Solution for 4y-6+2(4y+3)=-2(y+5) equation:

4y-6+2(4y+3)=-2(y+5)

We move all terms to the left:

4y-6+2(4y+3)-(-2(y+5))=0

We multiply parentheses

4y+8y-(-2(y+5))+6-6=0


We calculate terms in parentheses: -(-2(y+5)), so:

-2(y+5)

We multiply parentheses

-2y-10

Back to the equation:

-(-2y-10)


We add all the numbers together, and all the variables

12y-(-2y-10)=0

We get rid of parentheses

12y+2y+10=0

We add all the numbers together, and all the variables

14y+10=0

We move all terms containing y to the left, all other terms to the right

14y=-10

y=-10/14

y=-5/7