4y-4=2(2y-2)

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Solution for 4y-4=2(2y-2) equation: 



4y-4=2(2y-2)

We move all terms to the left:

4y-4-(2(2y-2))=0



We calculate terms in parentheses: -(2(2y-2)), so:

2(2y-2)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We get rid of parentheses

4y-4y+4-4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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