4y-4=13y+68

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Solution for 4y-4=13y+68 equation: 



4y-4=13y+68

We move all terms to the left:

4y-4-(13y+68)=0

We get rid of parentheses

4y-13y-68-4=0

We add all the numbers together, and all the variables

-9y-72=0

We move all terms containing y to the left, all other terms to the right

-9y=72

y=72/-9

y=-8

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