4y-4(3y+1)=-3-2(1-y)

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Solution for 4y-4(3y+1)=-3-2(1-y) equation:


Simplifying
4y + -4(3y + 1) = -3 + -2(1 + -1y)

Reorder the terms:
4y + -4(1 + 3y) = -3 + -2(1 + -1y)
4y + (1 * -4 + 3y * -4) = -3 + -2(1 + -1y)
4y + (-4 + -12y) = -3 + -2(1 + -1y)

Reorder the terms:
-4 + 4y + -12y = -3 + -2(1 + -1y)

Combine like terms: 4y + -12y = -8y
-4 + -8y = -3 + -2(1 + -1y)
-4 + -8y = -3 + (1 * -2 + -1y * -2)
-4 + -8y = -3 + (-2 + 2y)

Combine like terms: -3 + -2 = -5
-4 + -8y = -5 + 2y

Solving
-4 + -8y = -5 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-4 + -8y + -2y = -5 + 2y + -2y

Combine like terms: -8y + -2y = -10y
-4 + -10y = -5 + 2y + -2y

Combine like terms: 2y + -2y = 0
-4 + -10y = -5 + 0
-4 + -10y = -5

Add '4' to each side of the equation.
-4 + 4 + -10y = -5 + 4

Combine like terms: -4 + 4 = 0
0 + -10y = -5 + 4
-10y = -5 + 4

Combine like terms: -5 + 4 = -1
-10y = -1

Divide each side by '-10'.
y = 0.1

Simplifying
y = 0.1

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