4y-3=(2y+1)

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Solution for 4y-3=(2y+1) equation: 



4y-3=(2y+1)

We move all terms to the left:

4y-3-((2y+1))=0



We calculate terms in parentheses: -((2y+1)), so:

(2y+1)

We get rid of parentheses

2y+1

Back to the equation:

-(2y+1)



We get rid of parentheses

4y-2y-1-3=0

We add all the numbers together, and all the variables

2y-4=0

We move all terms containing y to the left, all other terms to the right

2y=4

y=4/2

y=2

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