4y-3(y+2)=7

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Solution for 4y-3(y+2)=7 equation: 



4y-3(y+2)=7

We move all terms to the left:

4y-3(y+2)-(7)=0

We multiply parentheses

4y-3y-6-7=0

We add all the numbers together, and all the variables

y-13=0

We move all terms containing y to the left, all other terms to the right

y=13

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