4y-28=2(y-4)

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Solution for 4y-28=2(y-4) equation: 



4y-28=2(y-4)

We move all terms to the left:

4y-28-(2(y-4))=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

4y-2y+8-28=0

We add all the numbers together, and all the variables

2y-20=0

We move all terms containing y to the left, all other terms to the right

2y=20

y=20/2

y=10

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