4y-2+3(3y+1)=-3(y+1)

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Solution for 4y-2+3(3y+1)=-3(y+1) equation:


4y-2+3(3y+1)=-3(y+1)

We simplify the equation to the form, which is simple to understand 
4y-2+3(3y+1)=-3(y+1)

Reorder the terms in parentheses
4y-2+(+9y+3)=-3*(y+1)

Remove unnecessary parentheses
+4y-2+9y+3=-3+*(+y+1+)

Reorder the terms in parentheses
4y-2+9y+3=+(-3y-3)

Remove unnecessary parentheses
+4y-2+9y+3=-3y-3

We move all terms containing y to the left and all other terms to the right. 
+4y+9y+3y=-3+2-3

We simplify left and right side of the equation. 
+16y=-4

We divide both sides of the equation by 16 to get y. 
y=-0.25

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