4y-12=8(y-3)

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Solution for 4y-12=8(y-3) equation: 



4y-12=8(y-3)

We move all terms to the left:

4y-12-(8(y-3))=0



We calculate terms in parentheses: -(8(y-3)), so:

8(y-3)

We multiply parentheses

8y-24

Back to the equation:

-(8y-24)



We get rid of parentheses

4y-8y+24-12=0

We add all the numbers together, and all the variables

-4y+12=0

We move all terms containing y to the left, all other terms to the right

-4y=-12

y=-12/-4

y=+3

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