4y-1+4y-1+5y+3+5y+3=112

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Solution for 4y-1+4y-1+5y+3+5y+3=112 equation: 



4y-1+4y-1+5y+3+5y+3=112

We move all terms to the left:

4y-1+4y-1+5y+3+5y+3-(112)=0

We add all the numbers together, and all the variables

18y-108=0

We move all terms containing y to the left, all other terms to the right

18y=108

y=108/18

y=6

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