4y+8=5/5y+8=6

Solution for 4y+8=5/5y+8=6 equation:

4y+8=5/5y+8=6

We move all terms to the left:

4y+8-(5/5y+8)=0


Domain of the equation: 5y+8)!=0

y∈R


We get rid of parentheses

4y-5/5y-8+8=0

We multiply all the terms by the denominator


4y*5y-8*5y+8*5y-5=0

Wy multiply elements

20y^2-40y+40y-5=0

We add all the numbers together, and all the variables

20y^2-5=0

a = 20; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·20·(-5)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*20}=\frac{-20}{40}
=-1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*20}=\frac{20}{40}
=1/2
$