4y+8=2y2+12

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Solution for 4y+8=2y2+12 equation: 



4y+8=2y^2+12

We move all terms to the left:

4y+8-(2y^2+12)=0

We get rid of parentheses

-2y^2+4y-12+8=0

We add all the numbers together, and all the variables

-2y^2+4y-4=0

a = -2; b = 4; c = -4;
Δ = b2-4ac
Δ = 42-4·(-2)·(-4)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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