4y+4=-8(y-2)

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Solution for 4y+4=-8(y-2) equation: 



4y+4=-8(y-2)

We move all terms to the left:

4y+4-(-8(y-2))=0



We calculate terms in parentheses: -(-8(y-2)), so:

-8(y-2)

We multiply parentheses

-8y+16

Back to the equation:

-(-8y+16)



We get rid of parentheses

4y+8y-16+4=0

We add all the numbers together, and all the variables

12y-12=0

We move all terms containing y to the left, all other terms to the right

12y=12

y=12/12

y=1

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