4y+31=7(y+7)

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Solution for 4y+31=7(y+7) equation: 



4y+31=7(y+7)

We move all terms to the left:

4y+31-(7(y+7))=0



We calculate terms in parentheses: -(7(y+7)), so:

7(y+7)

We multiply parentheses

7y+49

Back to the equation:

-(7y+49)



We get rid of parentheses

4y-7y-49+31=0

We add all the numbers together, and all the variables

-3y-18=0

We move all terms containing y to the left, all other terms to the right

-3y=18

y=18/-3

y=-6

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