4y+2=-1/3)8-12y)

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Solution for 4y+2=-1/3)8-12y) equation: 



4y+2=-1/3)8-12y)

We move all terms to the left:

4y+2-(-1/3)8-12y))=0

We multiply all the terms by the denominator


4y*3)8-12y))+2-(-1=0

Wy multiply elements

12y^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{24}=0$

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