4y+2(y-3)=10

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Solution for 4y+2(y-3)=10 equation: 



4y+2(y-3)=10

We move all terms to the left:

4y+2(y-3)-(10)=0

We multiply parentheses

4y+2y-6-10=0

We add all the numbers together, and all the variables

6y-16=0

We move all terms containing y to the left, all other terms to the right

6y=16

y=16/6

y=2+2/3

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