4y+2(3y-5)=20

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Solution for 4y+2(3y-5)=20 equation: 



4y+2(3y-5)=20

We move all terms to the left:

4y+2(3y-5)-(20)=0

We multiply parentheses

4y+6y-10-20=0

We add all the numbers together, and all the variables

10y-30=0

We move all terms containing y to the left, all other terms to the right

10y=30

y=30/10

y=3

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