4y+1=(y+(y-5))2

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Solution for 4y+1=(y+(y-5))2 equation:


Simplifying
4y + 1 = (y + (y + -5)) * 2

Reorder the terms:
1 + 4y = (y + (y + -5)) * 2

Reorder the terms:
1 + 4y = (y + (-5 + y)) * 2

Remove parenthesis around (-5 + y)
1 + 4y = (y + -5 + y) * 2

Reorder the terms:
1 + 4y = (-5 + y + y) * 2

Combine like terms: y + y = 2y
1 + 4y = (-5 + 2y) * 2

Reorder the terms for easier multiplication:
1 + 4y = 2(-5 + 2y)
1 + 4y = (-5 * 2 + 2y * 2)
1 + 4y = (-10 + 4y)

Add '-4y' to each side of the equation.
1 + 4y + -4y = -10 + 4y + -4y

Combine like terms: 4y + -4y = 0
1 + 0 = -10 + 4y + -4y
1 = -10 + 4y + -4y

Combine like terms: 4y + -4y = 0
1 = -10 + 0
1 = -10

Solving
1 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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