4y+16=1/3(1-y=4)

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Solution for 4y+16=1/3(1-y=4) equation: 



4y+16=1/3(1-y=4)

We move all terms to the left:

4y+16-(1/3(1-y)=0



Domain of the equation: 3(1-y)+16!=0

We move all terms containing y to the left, all other terms to the right

3(1-y)!=-16

y∈R



We add all the numbers together, and all the variables

4y-(1/3(-1y+1)+16=0

We multiply all the terms by the denominator


4y*3(-1y+1)+16-(1=0

We add all the numbers together, and all the variables

4y*3(-1y+1)=0

Wy multiply elements

12y^2(-=0

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