4y+12=-(6y+28)

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Solution for 4y+12=-(6y+28) equation: 



4y+12=-(6y+28)

We move all terms to the left:

4y+12-(-(6y+28))=0



We calculate terms in parentheses: -(-(6y+28)), so:

-(6y+28)

We get rid of parentheses

-6y-28

Back to the equation:

-(-6y-28)



We get rid of parentheses

4y+6y+28+12=0

We add all the numbers together, and all the variables

10y+40=0

We move all terms containing y to the left, all other terms to the right

10y=-40

y=-40/10

y=-4

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