4y+(y+1)=3-(y+1)

Solution for 4y+(y+1)=3-(y+1) equation:

4y+(y+1)=3-(y+1)

We move all terms to the left:

4y+(y+1)-(3-(y+1))=0

We get rid of parentheses

4y+y-(3-(y+1))+1=0


We calculate terms in parentheses: -(3-(y+1)), so:

3-(y+1)

determiningTheFunctionDomain
-(y+1)+3

We get rid of parentheses

-y-1+3

We add all the numbers together, and all the variables

-1y+2

Back to the equation:

-(-1y+2)


We add all the numbers together, and all the variables

5y-(-1y+2)+1=0

We get rid of parentheses

5y+1y-2+1=0

We add all the numbers together, and all the variables

6y-1=0

We move all terms containing y to the left, all other terms to the right

6y=1

y=1/6

y=1/6