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4y*5y=36
We move all terms to the left:
4y*5y-(36)=0
Wy multiply elements
20y^2-36=0
a = 20; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·20·(-36)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{5}}{2*20}=\frac{0-24\sqrt{5}}{40} =-\frac{24\sqrt{5}}{40} =-\frac{3\sqrt{5}}{5} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{5}}{2*20}=\frac{0+24\sqrt{5}}{40} =\frac{24\sqrt{5}}{40} =\frac{3\sqrt{5}}{5} $
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