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4y(y+25)=180
We move all terms to the left:
4y(y+25)-(180)=0
We multiply parentheses
4y^2+100y-180=0
a = 4; b = 100; c = -180;
Δ = b2-4ac
Δ = 1002-4·4·(-180)
Δ = 12880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12880}=\sqrt{16*805}=\sqrt{16}*\sqrt{805}=4\sqrt{805}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-4\sqrt{805}}{2*4}=\frac{-100-4\sqrt{805}}{8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+4\sqrt{805}}{2*4}=\frac{-100+4\sqrt{805}}{8} $
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