4y(3-y)=2y(3-2y)

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Solution for 4y(3-y)=2y(3-2y) equation: 



4y(3-y)=2y(3-2y)

We move all terms to the left:

4y(3-y)-(2y(3-2y))=0

We add all the numbers together, and all the variables

4y(-1y+3)-(2y(-2y+3))=0

We multiply parentheses

-4y^2+12y-(2y(-2y+3))=0



We calculate terms in parentheses: -(2y(-2y+3)), so:

2y(-2y+3)

We multiply parentheses

-4y^2+6y

Back to the equation:

-(-4y^2+6y)



We get rid of parentheses

-4y^2+4y^2-6y+12y=0

We add all the numbers together, and all the variables

6y=0

y=0/6

y=0

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