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4x=15x^2
We move all terms to the left:
4x-(15x^2)=0
determiningTheFunctionDomain -15x^2+4x=0
a = -15; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-15)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-15}=\frac{-8}{-30} =4/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-15}=\frac{0}{-30} =0 $
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