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4x^2=64000
We move all terms to the left:
4x^2-(64000)=0
a = 4; b = 0; c = -64000;
Δ = b2-4ac
Δ = 02-4·4·(-64000)
Δ = 1024000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1024000}=\sqrt{102400*10}=\sqrt{102400}*\sqrt{10}=320\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-320\sqrt{10}}{2*4}=\frac{0-320\sqrt{10}}{8} =-\frac{320\sqrt{10}}{8} =-40\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+320\sqrt{10}}{2*4}=\frac{0+320\sqrt{10}}{8} =\frac{320\sqrt{10}}{8} =40\sqrt{10} $
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