4x2=40x+44

Solution for 4x2=40x+44 equation:

4x^2=40x+44

We move all terms to the left:

4x^2-(40x+44)=0

We get rid of parentheses

4x^2-40x-44=0

a = 4; b = -40; c = -44;
Δ = b2-4ac
Δ = -402-4·4·(-44)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-48}{2*4}=\frac{-8}{8}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+48}{2*4}=\frac{88}{8}
=11
$