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4x^2=-3x+22
We move all terms to the left:
4x^2-(-3x+22)=0
We get rid of parentheses
4x^2+3x-22=0
a = 4; b = 3; c = -22;
Δ = b2-4ac
Δ = 32-4·4·(-22)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-19}{2*4}=\frac{-22}{8} =-2+3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+19}{2*4}=\frac{16}{8} =2 $
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