4x2-9x+4=0

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Solution for 4x2-9x+4=0 equation:



4x^2-9x+4=0
a = 4; b = -9; c = +4;
Δ = b2-4ac
Δ = -92-4·4·4
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{17}}{2*4}=\frac{9-\sqrt{17}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{17}}{2*4}=\frac{9+\sqrt{17}}{8} $

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