If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-9=0
a = 4; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·4·(-9)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*4}=\frac{-12}{8} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*4}=\frac{12}{8} =1+1/2 $
| 2.5x=0.0087 | | 4x2-9=0, | | (x-4)×(x-4)=144 | | 24+4y-6=15y-10-4y | | 3(y÷4)=4(y-6) | | -7=5x-9/3 | | 9x-124=-x+176 | | (6)x-x=10 | | 4p+9=−5 | | 1/5÷f=7 | | -8-12e=120 | | −4p+9=−5−4p+9=−5 | | 15+7x=10x | | 6x+x(x-5)=3(2-3x) | | 73-w=161 | | 6×x-x=10 | | 2.3x=8 | | 54-8y=y | | 3. 2x+3=-3x+6 | | -8+12e=120 | | 8t+4=3t+19 | | (14-3c)=7c=94 | | -9(x-1)=-10x | | -2(5s-4)-8=-3(7s+3)-4 | | 18=12e=-20 | | 17c–14c=12 | | (6)x-6=10 | | 6x+3=18+6x | | 5u+27=8u | | 1/3^x-1=9 | | (q-2)+1=14 | | 10=25-3p |