If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-8x+2=0
a = 4; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·4·2
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{2}}{2*4}=\frac{8-4\sqrt{2}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{2}}{2*4}=\frac{8+4\sqrt{2}}{8} $
| -2(6-3n)+27n=-3(n-8) | | 110+.20x=70+.40x | | 3n-2(n+8)=-8 | | -5n-3(n+2)=18 | | 8(-2n+.25)=-46 | | -1+5x+6x=-67 | | v-1=2v | | 3x-68=80+7x | | 6m-m=5/6(6m-12) | | 3x+16-7x=7 | | f+1/4=-7/2f= | | 3x=(4*60) | | -19+x=23 | | 3k/5=5 | | 4-1(5p-4)=83 | | 7-5z=1=5z | | 11x=2x-90 | | n2-8n+15=0 | | 16x(2x-1)=0 | | 6=t/4+8 | | 5h」9-4=H | | -6=-1-j | | 3(x+4)–8x=21 | | 3-2v=-23 | | -1+-1s=-4 | | -4(2x-3)=92 | | 8y-85=2y=35 | | 9=2y+17 | | 5(−2x−3)−4x−5= 7878 | | |3k–2|=7 | | 4(5x+)=14x+30 | | 3x+15=2x-4x |