4x2-60x+9=0

Solution for 4x2-60x+9=0 equation:

4x^2-60x+9=0

a = 4; b = -60; c = +9;
Δ = b2-4ac
Δ = -602-4·4·9
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-24\sqrt{6}}{2*4}=\frac{60-24\sqrt{6}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+24\sqrt{6}}{2*4}=\frac{60+24\sqrt{6}}{8}
$