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4x^2-45x+81=0
a = 4; b = -45; c = +81;
Δ = b2-4ac
Δ = -452-4·4·81
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-27}{2*4}=\frac{18}{8} =2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+27}{2*4}=\frac{72}{8} =9 $
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