4x2-44x+90=0

Solution for 4x2-44x+90=0 equation:

4x^2-44x+90=0

a = 4; b = -44; c = +90;
Δ = b2-4ac
Δ = -442-4·4·90
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-4\sqrt{31}}{2*4}=\frac{44-4\sqrt{31}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+4\sqrt{31}}{2*4}=\frac{44+4\sqrt{31}}{8}
$