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4x^2-2x+6=36
We move all terms to the left:
4x^2-2x+6-(36)=0
We add all the numbers together, and all the variables
4x^2-2x-30=0
a = 4; b = -2; c = -30;
Δ = b2-4ac
Δ = -22-4·4·(-30)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-22}{2*4}=\frac{-20}{8} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+22}{2*4}=\frac{24}{8} =3 $
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