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4x^2-250=0
a = 4; b = 0; c = -250;
Δ = b2-4ac
Δ = 02-4·4·(-250)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*4}=\frac{0-20\sqrt{10}}{8} =-\frac{20\sqrt{10}}{8} =-\frac{5\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*4}=\frac{0+20\sqrt{10}}{8} =\frac{20\sqrt{10}}{8} =\frac{5\sqrt{10}}{2} $
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