4x2-18x-93=-3

Solution for 4x2-18x-93=-3 equation:

4x^2-18x-93=-3

We move all terms to the left:

4x^2-18x-93-(-3)=0

We add all the numbers together, and all the variables

4x^2-18x-90=0

a = 4; b = -18; c = -90;
Δ = b2-4ac
Δ = -182-4·4·(-90)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-42}{2*4}=\frac{-24}{8}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+42}{2*4}=\frac{60}{8}
=7+1/2
$